Help with undefined index: Errors
Posted: Fri Nov 02, 2012 4:38 pm
How's it going guys? I was looking for tutorials on the net and came across this one below. I have everything running properly sort of and can't seem to figure out and racking my brain with the Undefined index: name_list error on line 24.
I will try and attach the code. Also in the Change the money text box there is a MySQL error that says Undefined variable: select_money on line 70.
I am thinking there is a "checking" situation i am missing that I am just not seeing. I was reading about this type of error and that the error is not really a problem but id like to figure it out. Please help!!! P.S here is the original place where i found the tutorial in case others would like to see it. http://www.dreamincode.net/forums/topic ... on-part-1/


Code: Select all
<?php include_once("connect.php"); ?>
<html>
<head>
<title>TestPage2</title>
</head>
<body>
<?php
if (isset($_POST['submit']))
{
$sql = "INSERT INTO users SET id = '', name = '".$_POST['name']."'";
$res = mysql_query($sql);
echo "".$_POST['name']." ADDED";
}
// the line below is just selecting data from users table and adding it to result
$result = mysql_query("SELECT name, id, money FROM users ORDER BY id DESC") or die(mysql_error());
// this is assigning some html for the drop down menu along with the some php and the data from result
$member_list = "";
while($row = mysql_fetch_array($result))
{
if($row['name'] == $_POST['name_list'])
{
$member_list .= "<option selected =\"selected\"value=\"".$row['name']."\">".$row['name']."</option>";
}
else
{
$member_list .= "<option value=\"".$row['name']."\">".$row['name']."</option>";
}
}
// the following below happend when you hit search and what it does is select data on the name you clicked on from the menu.
if(isset($_POST['select']) or isset($_POST['update']))
{
$sql = "SELECT * FROM users WHERE name = '".mysql_real_escape_string($_POST['name_list'])."'";
$query = mysql_query($sql) or die(mysql_error());
$row = mysql_fetch_array($query);
$select_money = htmlspecialchars($row->money);
}
// Updating the database with the information entered.
if(isset($_POST['update']))
{
$result = mysql_query("UPDATE users SET money = '".mysql_real_escape_string($_POST['money'])."' WHERE name = '" .mysql_real_escape_string($_POST['name_list']). "'") or die(mysql_error());
echo "".$_POST['name_list']."'s money have been changed.";
}
?>
<form method="post">
<p>
<center>
<p>ENTER NAME<br />
<input type="text" name="name" id="name" />
<br />
<input type="submit" name="submit" id="submit" value="Submit" />
</p>
<p><br />
<span>
Select a Name
<select name="name_list" class="textbox" id="name_list">
<option value="<?php echo htmlspecialchars($_GET['user']); ?>">Select</option>
<?php echo $member_list; ?>
</select>
</span>
<input type="submit" name="select" id="select" onfocus="if(this.blur)this.blur()" value="Select">
<br />
Change the Money
<input type="text" name="money" id="money" value="<?php echo $select_money; ?>">
<br />
<input type="submit" name="update" id="update" value="Update">
<br />
</p>
<p> </p>
<table width="50%" border="2" cellspacing="1" cellpadding="0">
<tr align="center">
<td colspan="3">Users Information</td>
</tr>
<tr align="center">
<td>ID</td>
<td>Name</td>
<td>Money</td>
</tr>
<?php
$result = mysql_query("SELECT * FROM users") or die(mysql_error());
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array($result))
{
// print out the contents of each row into a table?>
<tr>
<td><label for="<?php echo $row['id']; ?>">
<?php
$name2=$row['id'];
echo "$name2";
?>
</label></td>
<td><?php echo $row['name'] ?></td>
<td><?php echo $row['money'] ?></td>
</tr>
<?php } ?>
</table>
<p> </p>
</center>
</p>
</form>
</body>
</html>